This is a most bewildering sequel to the last effect. It fits in well when there is one or more who may think they are acute enough to have figured out some discrepancy in the figuring of the first trick.

The performer removes the two black Aces from the spectator’s pack. He does this by fanning through the cards, bringing the Aces to the face of the deck, and then removes them, at the same time secretly bringing away another card behind the second card (three, in all) which we shall call the Ace of Spades. The rest of the deck is given the spectator.

He is told to deal onto the table in a face down heap as many cards as he pleases, counting them aloud. When he has done so, the performer, holding his cards face down, lifts the top two together to show the Ace of Spades (face) and says “And this Ace of Spades makes one more.” He places the card (two) face down on the dealt card, naming, as he does so, the number that appear to lie in the pile now.

The spectator now removes any card from among those he has left, notes it, and places it face down on the Ace of Spades (?). “That makes one more,” the performer remarks, mentioning the total. “I’ll place the Ace of Clubs on next,” and he does so. The balance of the deck is put on top of all.

Attention is now called to the fact that an Ace of Spades lies at the face of the spectator’s card and an Ace of Clubs at its back. It is also made clear how many cards lie above his. Actually the number is one less than there seems. The spectator now picks up the deck and deals onto the performer’s hand down to and including the Ace of Clubs. That is, he thinks he does, but his chosen card becomes the top one on the performer’s pile.

Using a double lift the performer shows the top card (?) to be the Ace of Clubs, as it should be. The spectator puts his top card, believing it to be his very own, into the center of his packet. And then he is told to look at the next one, the Ace of Spades, which makes certain that he got the right one.

Taking the Ace of Spades from the spectator, the performer puts it on the back of his Ace of Clubs, the spectator’s card therefore going between the two. They are placed on top of the spectator’s pile and he is asked if, by a single cut, he can cause the two black aces to find his card. It will be declared impossible, his chosen card being in the center of the packet. However, the spectator cuts his packet and examines the cards. His selected pasteboard is found between the two Aces, and the pack may be counted and found complete.